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One way to go about this is, since you see 27 in answer choices, and bottle 1 is 7:2 => 7x + 2x => 9x; multiplying 7:2 by 3 => 21:6

You can also see 13, in option (B), and bottle 2 is 9:4 => 9x + 4x => 13x; so we keep 9:4 as is.

Now mixing bottle 1 and bottle 2 => 21 + 9 : 6 + 4 => 30:10 => 3:1

You get milk and water in 3:1 ratio, so 27:13 is the correct answer.
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Let's assume Bottle 1 has 9x amount of solution, i.e. 7x of milk and 2x of water as per the given.
Likewise, let's assume Bottle 2 has 13y amount of solution, i.e. 9y of milk and 4y of water.

Now, as our next step, we are told that the new ratio obtained should be 3:1.

If we put this in work, we are told that the ratio of milk in the overall solution should be:
(7x+9y)/(9x+13y)=3/4
or (28x + 36y) = (27x + 39y)

Finally, it's x=3y

Plugging in the value of x in our combined solutions of Bottle 1 and 2 would get us = 9x:13y or 9(3y):13y = 27:13. Option B

(Note: In mixture questions, going by a diagram in your rough work really helps to understand better and solve efficiently)

Bunuel
Bottle 1 contains a mixture of milk and water in 7 : 2 ratio and Bottle 2 contains a mixture of milk and water in 9 : 4 ratio. In what ratio of volumes should the liquids in Bottle 1 and Bottle 2 be combined to obtain a mixture of milk and water in 3 : 1 ratio?

A. 27 : 14
B. 27 : 13
C. 27 : 16
D. 27 : 18
E. 27 : 17


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