Bunuel
Three vessels whose capacities are in the ratio of 3:2:1 are completely filled with milk mixed with water. The ratio of milk and water in the mixture of vessels are 5:2, 4:1 and 4:1 respectively. Taking 1/3 of first, 1/2 of second and 1/7 of third mixture, a new mixture kept in a new vessels is prepared. The percentage of water in the new mixture is..
(A) 20%
(B) 24%
(C) 28%
(D) 32%
(E) 36%
You need almost no calculations for this question.
First thing I would note here is that the second and third vessels have the same solution. (ratio of milk : water is 4:1)
Also, since their capacities are 3:2:1, assuming capacities of 3lt, 2 lt and 1 lt, I see that 1 ltr was taken from first vessel (1/3rd), 1 ltr was taken from second vessel (1/2) and 1/7 ltr was taken from third vessel.
So we have 1 ltr of solution with milk:water 5:2 ( which is 28.56% water. Note here that we know 1/7 = 14.28% so 2/7 = 28.56%)
and 1(1/7) ltr of solution with milk:water 4:1 (which is 20% water)
When mixed together, water concentration will be between 20% and 28.56%. Both solutions are taken almost in same quantities with the 20% water solution a little bit extra. So their avg concentration will lie almost in the middle but a tiny bit closer to 20%. Hence, 24% fits perfectly and nothing else does.
Answer (B)