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Bunuel
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yashikaaggarwal
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Bunuel KarishmaB
Do we have any other method to solve this problem. I tried solving algebraically as making individual equations for 3 vessels and adding as
3/7(capacity from ratio) * 1/3(Amount taken from tank) * 2/7(water ratio in that vessel)
I did the same for all the 3 vessels. But I am not getting the correct results

Thank You
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Hi Bunuel, could you please share the solutions? Thanks!
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Algebraically it can be done as the below:

Taking 3:2:1 as 3x:2x:x,

Water component in each of the vessels is: 3x - 2/7 (as ratio of milk to water is 5:2)
2x and x - 1/5 (as ratio of milk to water is 4:1 for both)

Water in the final mixture / Total final mixutre * 100 % =
x(1/3*2/7*3 + 1/2*1/5*2 + 1/7*1/5*1) whole divided by x(1/3*3 + 1/2*2 + 1/7*1) * 100%
= 18/35 * 7/15 * 100% (x cancels out from numerator and denominator)
= 24% (B)
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