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Bunuel
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Can this be done through alligation?
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RishikaShah07
Can this be done through alligation?
24% tin and 100% tin added gives final 48% tin

24100
48
5224

52:24 = 13:6

We have 100 kg of existing alloy, let x be the added tin,

\(\frac{100}{x} = \frac{13}{6}\)

x = \(\frac{600}{13}\) = approx. 46
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Step-by-step Breakdown:

We are told:

* The original alloy weighs **100 kg**, and **24%** of it is tin.
* That means:

{Tin} = 24{ kg}, {Other metals} = 76{ kg}

We **add x kg of pure tin**, so:

* **New weight of tin = 24 + x**
* **New total weight = 100 + x**

We want the percentage of tin to become **48% (double of 24%)**, so we set up the equation:

{24 + x}/{100 + x} = {48}/{100}

### **Step 1: Solve the equation**

{24 + x}/{100 + x} = {48}/{100}

Cross-multiplying:

100(24 + x) = 48(100 + x)

2400 + 100x = 4800 + 48x

100x - 48x = 4800 - 2400
52x = 2400
x = {2400}/{52} = {600}/{13}

### **Step 2: Approximate**

x = {600}/{13} ~ 46.15
To the **nearest kg**, the answer is:
{46 \text{ kg}}

✅ Final Answer: (D) 46
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