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10 Feb 2022, 06:15
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:25) correct
20%
(01:34)
wrong
based on 131
sessions
History
Date
Time
Result
Not Attempted Yet
If the hypotenuse of an isosceles right triangle has length of 8, then the area of the triangle is
A. 4
B. 4√2
C. 8
D. 8√2
E. 16
A. 4
B. 4√2
C. 8
D. 8√2
E. 16
10 Feb 2022, 07:46
Kudos
Bookmarks
Bunuel
Let's sketch the given information.
Let x = the length of each of the two equal sides
From here, we can apply the Pythagorean theorem to write: x² + x² = 8²
Simplify: 2x² = 64
Divide both sides of the equation by 2 to get: x² = 32
This means x = √32 [you'll see why I didn't bother simplifying √32 shortly]
So we have the following:
Triangle area = (base)(height)/2 = (√32)(√32)/2 = 32/2 = 16
Answer: E
26 Apr 2023, 08:06
Kudos
Bookmarks
Bunuel
\(a\sqrt{2}=8\)
So, \(a^2 = 32\)
Thus, Area of the isosceles right triangle will be \(\frac{1}{2}a^2 = \frac{32}{2} = 16\), Answer must be (E)
