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07 Apr 2022, 03:00
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E
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Difficulty:
75%
(hard)
Question Stats:
60% (02:56) correct
40%
(02:37)
wrong
based on 164
sessions
History
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What is the probability of total score of 7 if 4 six-sided fair dice are thrown ?
A. 3/432
B. 1/324
C. 1/162
D. 1/108
E. 5/324
A. 3/432
B. 1/324
C. 1/162
D. 1/108
E. 5/324
09 Apr 2022, 05:54
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{1,1,1,4},{1,1,2,3},{1,2,2,2}
Possible Combinations 4+12+4=20
Total Combinations=6*6*6*6
Prob = 20/6*6*6*6 = 5/324
Posted from my mobile device
Possible Combinations 4+12+4=20
Total Combinations=6*6*6*6
Prob = 20/6*6*6*6 = 5/324
Posted from my mobile device
31 Aug 2024, 03:57
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧
Given that 4 six-sided fair dice are rolled and we need to find what is the probability of getting a total score of 7.
As we are rolling four dice => Number of cases = 6*6*6*6
To get the sum of the 4 rolls as 7 we have following cases:
=> P(Sum=7) = \(\frac{20}{6*6*6*6}\) = \(\frac{5}{324}\)
So, Answer will be E
Hope it helps!
Watch the following video to MASTER How to Solve Dice Rolling Probability Problems
Given that 4 six-sided fair dice are rolled and we need to find what is the probability of getting a total score of 7.
As we are rolling four dice => Number of cases = 6*6*6*6
To get the sum of the 4 rolls as 7 we have following cases:
- (1,1,1,4) -> Now this 4 can come in any of the 4 dice -> 4 cases
- (1,1,2,3) -> 3 can come in any of the 4 dices, 2 can come in any of the remaining 3 dices, remaining 2 dices will have 1 -> 4 * 3 = 12 cases
- (1,2,2,2) -> 1 can come in any of the 4 dices and 2 will come in other dices -> 4 cases
=> P(Sum=7) = \(\frac{20}{6*6*6*6}\) = \(\frac{5}{324}\)
So, Answer will be E
Hope it helps!
Watch the following video to MASTER How to Solve Dice Rolling Probability Problems
