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05 May 2022, 14:23
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:15) correct
19%
(01:34)
wrong
based on 171
sessions
History
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Time
Result
Not Attempted Yet
A box contains 4 red chips and 2 black chips. If 2 chips are randomly selected without replacement, what is the probability the two selected chips are different colors?
(A) 4/15
(B) 1/3
(C) 2/5
(D) 8/15
(E) 2/3
(A) 4/15
(B) 1/3
(C) 2/5
(D) 8/15
(E) 2/3
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06 May 2022, 09:55
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BrentGMATPrepNow
No takers??? Okay, here's my solution:
P(different colors) = P(1st chip is red AND 2nd chip is black OR 1st chip is black AND 2nd chip is red)
= [P(1st chip is red) x P(2nd chip is black)] + [P(1st chip is black) x P(2nd chip is red)]
= [4/6 x 2/5] + [2/6 x 4/5]
= 8/30 + 8/30
= 16/30
= 8/15
Answer: D
06 May 2022, 10:02
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Given: A box contains 4 red chips and 2 black chips.
Asked: If 2 chips are randomly selected without replacement, what is the probability the two selected chips are different colors?
Probability = 4C1*2C1/6C2= 4*2/15 = 8/15
IMO D
Asked: If 2 chips are randomly selected without replacement, what is the probability the two selected chips are different colors?
Probability = 4C1*2C1/6C2= 4*2/15 = 8/15
IMO D
