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Bunuel
If x - y = 2 and x² - y² = 16, then x³ - y³ = ?

A. 97
B. 98
C. 99
D. 100
E. 152

Take: x² - y² = 16
Factor: (x + y)(x - y) = 16
Substitute to get: (x + y)(2) = 16
Divide both sides of the equation by 2 to get: x + y = 8

We now have the following system of equations:
x - y = 2
x + y = 8
Add the two equations to get: 2x = 10, which means x = 5
Once we know x = 5, we can plug this value into one of the two equations to learn that y = 3

Now that we know the values of x and y, x³ - y³ = 5³ - 3³ = 125 - 27 = 98

Answer: B
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BrentGMATPrepNow
Bunuel
If x - y = 2 and x² - y² = 16, then x³ - y³ = ?

A. 97
B. 98
C. 99
D. 100
E. 152

Take: x² - y² = 16
Factor: (x + y)(x - y) = 16
Substitute to get: (x + y)(2) = 16
Divide both sides of the equation by 2 to get: x + y = 8

We now have the following system of equations:
x - y = 2
x + y = 8
Add the two equations to get: 2x = 10, which means x = 5
Once we know x = 5, we can plug this value into one of the two equations to learn that y = -3

Now that we know the values of x and y, x³ - y³ = 5³ - (-3)³ = 125 - (-27) = 152

Answer: E


Hi BrentGMATPrepNow
if x=5 and y=-3
x-y=5-(-3)=8, the stem mention x-y=2. Am I missing something?

Regards,
R
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rseglia

Hi BrentGMATPrepNow
if x=5 and y=-3
x-y=5-(-3)=8, the stem mention x-y=2. Am I missing something?

Regards,
R

No, you're absolutely right.
Once I'd determined x = 5, I have no idea how I then concluded y = -3, when y actually equals 3.
I have edited my response accordingly.

Thanks for the heads up!
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