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Bunuel
Elmo makes N sandwiches for a fundraiser. For each sandwich he uses B globs of peanut butter at 4 cents per glob and J blobs of jam at 5 cents per glob. The cost of the peanut butter and jam to make all the sandwiches is 2.53. Assume that B, J and N are all positive integers with N > 1. What is the cost of the jam Elmo uses to make the sandwiches?

(A) 1.05
(B) 1.25
(C) 1.45
(D) 1.65
(E) 1.85

Let B = the total number of peanut butter globs and J = the total number of jam globs.

Since B globs of peanut butter are used to make N sandwiches, the number of peanut butter globs per sandwich = \(\frac{B}{N}\)
Since J globs of jam are used to make N sandwiches, the number of jam globs per sandwich = \( \frac{J}{N}\)
Implication:
B and J must both be divisible by N.

Since the total cost of the 4-cent peanut butter globs and 5-cent jam globs is 235 cents, we get:
4B+5J=235

We can PLUG IN THE ANSWERS, which represent the total cost of the jam (5J).
When the correct answer is plugged in, B and J will both be divisible by N.

B: 5J = 125 --> J=25
Since 4B+5J=253 and 5J=125, 4B=128 --> B=32
J=25 and B=32 have no factors in common other than 1.
Thus, this answer choice does not yield a viable option for N.
Eliminate B.

D: 5J = 165 --> J=33
Since 4B+5J=253 and 5J=165, 4B=88 --> B=22
J=33 and B=22 are both divisible by 11.
Thus:
N=11, implying that 11 sandwiches are made with J=33 globs of jam and B=22 globs of peanut butter.
Success!

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Cost of all sandwich = $ 2.53 = 253 ¢
If he she makes N sandwich....each cost same .... then...N × [ cost price ] = 253 ¢
So...N is a factor of 253 ......now there are only 4 factors of 253..... 1, 11, 23 and 253....but N ≠ 1, 253 .......
So...N must be 11....or 23 .... But...if she makes 23 sandwich...then each will cost = 11 ¢ ......but peanut butter glob worth 4 ¢ ... and jam glob worth 5 ¢ ...... and.... [ multiple of 5 ] + [ multiple of 4 ] ≠ 11 .....
So.....she must've made 11 sandwich....then each cost 23 ¢ ...... and....23 = [ 3 × 5 ] + [ 2 × 4 ] .....so it matches.....
So....cost of jam in 1 sandwich = 3 × 5 = 15 ¢ ......so..... cost of jam in 11 sandwich = 11 × 15 = 165 ¢ = 1.65 $

! nah id win!
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