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09 Jun 2022, 01:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
64% (02:20) correct
36%
(02:15)
wrong
based on 212
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History
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During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)
(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6
Are You Up For the Challenge: 700 Level Questions
(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6
Are You Up For the Challenge: 700 Level Questions
09 Jun 2022, 02:13
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The rate of surging is 1/4 mile in 25 days.
Thus, in 100 days, a 1-mile surge will be complete.
Or, in 100 days, 5280 feet surge.
Since in 1 day, there are 24 hours,
Thus, 1 foot surge = 100*24/5280 = 5/11 hours.
The correct answer will be C.
Thus, in 100 days, a 1-mile surge will be complete.
Or, in 100 days, 5280 feet surge.
Since in 1 day, there are 24 hours,
Thus, 1 foot surge = 100*24/5280 = 5/11 hours.
The correct answer will be C.
09 Jun 2022, 02:29
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We know it takes 25 days to surge 1/4 miles.
It means that it takes 25X24 hours to surge 1/4*5280 feet.
How many hours does it take the glacier to cover one foot?
(25*24)/(5280/4)=5/11
The answer is thus (C).
It means that it takes 25X24 hours to surge 1/4*5280 feet.
How many hours does it take the glacier to cover one foot?
(25*24)/(5280/4)=5/11
The answer is thus (C).
