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08 Aug 2022, 22:24
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
70% (02:45) correct
30%
(02:38)
wrong
based on 236
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A mixture of sugar is created by mixing sugar of costlier variety and cheaper variety in the ratio of 2:3 respectively. If this ratio is reversed, the price per kg of the mixture increases by 20%. Find the ratio of the price of the costlier variety to cheaper variety.
A. 5:3
B. 7:4
C. 7:5
D. 5:4
E. 8:3
Source : Wizako
A. 5:3
B. 7:4
C. 7:5
D. 5:4
E. 8:3
Source : Wizako
08 Aug 2022, 23:05
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1.2(2x+3y)=3x+2y
0.6x=1.6y
→x=8/3 y
Option E
Posted from my mobile device
0.6x=1.6y
→x=8/3 y
Option E
Posted from my mobile device
General Discussion
samarpan.g28
16 Dec 2024, 09:28
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Let the price of the costlier is x per unit, and the price of the cheaper is y per unit.
For the first variety, the overall price let's say 100, so 2x+3y=100
For the second variety, the ratio is reversed and the price is 120, so 3x+2y=120.
We need to find x/y.
Either solve the equations or take their ratio: 2x+3y / 3x+2y = 100/120 or, 12x+18y = 15x+10y or, 3x=8y or, x/y=8/3. Option (E) is correct.
For the first variety, the overall price let's say 100, so 2x+3y=100
For the second variety, the ratio is reversed and the price is 120, so 3x+2y=120.
We need to find x/y.
Either solve the equations or take their ratio: 2x+3y / 3x+2y = 100/120 or, 12x+18y = 15x+10y or, 3x=8y or, x/y=8/3. Option (E) is correct.
Suraj0184
