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11 Aug 2022, 07:51
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
62% (01:42) correct
38%
(01:27)
wrong
based on 611
sessions
History
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Time
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Not Attempted Yet
A manufacturer of thermal flasks conducts an experiment on one of their flasks. The flask is filled with water at a temperature of 81℃, and placed in a refrigerator set to a temperature of 0℃. If the temperature in degrees celsius is reduced by one third every six hours, what is the temperature of the water after 24 hours?
A. −27℃
B. 1℃
C. 16℃
D. 24℃
E. 54℃
Not satisfied with OA. Please help.
A. −27℃
B. 1℃
C. 16℃
D. 24℃
E. 54℃
Not satisfied with OA. Please help.
11 Aug 2022, 08:19
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MKaizer123
I'm guessing that you divided by 3 rather than subtracting one third...?
T0 = 81
T1 = 81 - (81/3) = 81 - 27 = 54
T2 = 54 - (54/3) = 54 - 18 = 36
T3 = 36 - (36/3) = 36 - 12 = 24
T4 = 24 - (24/3) = 24 - 8 = 16
Answer choice C.
11 Aug 2022, 15:02
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MKaizer123
The key is to recognize that it is the temperature at the beginning of each 6 hour period that is reduced by 1/3 over that period and not simply subtracting a constant 1/3 of the original temperature (except for the for the first 6 hours)
This makes sense thermodynamically because the rate of temperature drop is proportional to the temperature difference.
As the temperature decreases, so does the rate of decrease. For example, the first decrease is 1/3 the beginning temperature and the rate for the second decrease is 1/3*2/3 of the beginning temperature, a smaller absolute reduction.
And you can see that in the Dude's response above.
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