As we know,
Work = Rate x TimeHint: Work is always 1 in such scenario (i.e. filling a water tank)
Now, suppose A takes A hours to fill the complete tank when working alone, and B takes B hours to do the same job working alone. So, rate of A becomes 1/A and that of B becomes 1/B
When B starts draining at 3PM:1 = [{(Rate of A working alone from 2PM to 3PM x 1 Hour from 2PM to 3PM)} + {(Combined Rate of A and B working together from 3PM to 10PM) x (7 hours Combined time from 3PM to 10PM)}]
1 = [(1/A x 1) + (1/A - 1/B) x 7] (As A fills the water and B drains out, so combined rate = Rate of A - Rate of B)
1 = 1/A + 7/A - 7/B
1= 8/A - 7/B ---------- (Eq. 1)
Similarly, when B starts draining at 4PM:1 = [{(Rate of A working alone from 2PM to 4PM x 2 Hour from 2PM to 4PM)} + {(Combined Rate of A and B working together from 4PM to 6PM) x (2 hours Combined time from 4PM to 6PM)}]
1 = [(1/A x 2) + (1/A - 1/B) x 2]
1 = 2/A + 2/A - 2/B
2 = 4/A - 2/B --------- (Eq. 2)
After solving (Eq. 1) and (Eq. 2) simultaneously (i.e. multiplying (Eq. 1) by 2 on both sides and multiplying (Eq. 2) by 7 on both sides to make coefficients of variable B same:
(Eq. 2) becomes: 7 = 28/A - 14/B
(Eq.1) becomes: 2 = 16/A - 14/B
After subtracting (Eq. 1) from (Eq. 2):
5 = 12/A - 0
So, A = 12/5 hours = 12/5 x 60 minutes
= 144 minutes Answer!Hence, Choice B must be correct!