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Updated on: 30 Aug 2022, 01:55
Originally posted by Aabhash777 on 29 Aug 2022, 21:38.
Last edited by Bunuel on 30 Aug 2022, 01:55, edited 1 time in total.
Last edited by Bunuel on 30 Aug 2022, 01:55, edited 1 time in total.
Renamed the topic and edited the question.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
56% (01:51) correct
44%
(01:47)
wrong
based on 135
sessions
History
Date
Time
Result
Not Attempted Yet
A coach has to form a team of 4 players out of 7 players. Amy and Bob are among the 7 players. What percent of teams that have Amy, will also include Bob?
A. 20%
B. 25%
C. (1,000/35)%
D. 50%
E. 75%
A. 20%
B. 25%
C. (1,000/35)%
D. 50%
E. 75%
29 Aug 2022, 21:52
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So, we need to find
Teams with Bob and Amy / Teams with Amy
Let us find the number of teams where Amy is certain:
We have 7 players in total and Amy has to be in the team so apart from Amy, we have 6 available players and 3 more slots to pick so
Number of teams with Amy = 6c3 = 20
Number of teams with both Bob and Amy :
If both Bob and Amy HAVE TO BE in the team, it leaves us with 5 available players and 2 remaining slots which can be done in 5c2 ways = 10
So, percent = (10/20) * 100 = 50%
Answer - D
Posted from my mobile device
Teams with Bob and Amy / Teams with Amy
Let us find the number of teams where Amy is certain:
We have 7 players in total and Amy has to be in the team so apart from Amy, we have 6 available players and 3 more slots to pick so
Number of teams with Amy = 6c3 = 20
Number of teams with both Bob and Amy :
If both Bob and Amy HAVE TO BE in the team, it leaves us with 5 available players and 2 remaining slots which can be done in 5c2 ways = 10
So, percent = (10/20) * 100 = 50%
Answer - D
Posted from my mobile device
30 Aug 2022, 06:17
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I think this question can be solved without any calculation. The intuition works here as half the time, Bob will be a part of Amy team and the other half time, Bob won't be a part of Amy team. Hence 50% can be marked directly basis intuition if we run short on time/ to save time in this ques.
