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↧↧↧ Detailed Video Solution to the Problem ↧↧↧



Method 1: Logic

Two fair six-sided dice, each numbered 1 to 6, are rolled once. What is the probability of getting less than two even numbers


As we are rolling two fair dice so there is equal probability of getting any of the following cases
(E,E), (E,O), (O,E), (O,O) where O is Odd and E is Even

P(Getting Less than 2 even) = Probability of getting (E,O), (O,E), (O,O) = \(\frac{3}{4}\)

Method 2: Algebra

Two fair six-sided dice, each numbered 1 to 6, are rolled once.

As we are rolling 2 dice => Number of cases = \(6^2\) = 36

What is the probability of getting less than two even numbers

P(Less than two even) = 1 - P(2 even)

We have two places and we can get even in both the places
=> Number of cases = 3*3 = 9
[ as we have 3 even numbers 2, 4, 6 ]

P(Getting Less than 2 even) = 1 - P(2 even) = 1 - \(\frac{9}{36}\) = 1 - \(\frac{1}{4}\) = \(\frac{3}{4}\)

So, Answer will be D
Hope it helps!

Playlist on Solved Problems on Probability here

Watch the following video to MASTER Dice Rolling Probability Problems

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