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26 Sep 2022, 06:13
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88% (01:31) correct
12%
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One worker can perform a certain task in 3 hours. A second worker can perform the same task in 7 hours. If both workers work together (but separately) on the task, how long in hours will it take them to complete 2/7 of the task?
A. 5/14
B. 3/5
C. 7/10
D. 10/7
E. 5/3
A. 5/14
B. 3/5
C. 7/10
D. 10/7
E. 5/3
26 Sep 2022, 06:21
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Take total work=21U (LCM of 3 &7)
Worker I completes work in 3 hours.
i.e. 7U/hour
Worker II completes work in 7 hours.
i.e. 3U/hour
When both work together, they complete 7+3=10 Unit/hour
To complete 2/7 of work i.e. 2*21/7= 6U work, they will have to work 6/10 or 3/5 hours.
Option B is the correct answer
Posted from my mobile device
Worker I completes work in 3 hours.
i.e. 7U/hour
Worker II completes work in 7 hours.
i.e. 3U/hour
When both work together, they complete 7+3=10 Unit/hour
To complete 2/7 of work i.e. 2*21/7= 6U work, they will have to work 6/10 or 3/5 hours.
Option B is the correct answer
Posted from my mobile device
17 Oct 2022, 01:41
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1st Worker work in one hour - 1/3
2nd Worker work in one hour - 1/7
1st Worker + 2nd Worker work in one hour = 1/3 + 1/7 = 10/21
Complete work is completed by them in 21/10 hours
2/7th of the work is completed in 2/7*21/10 = 3/5 hours
2nd Worker work in one hour - 1/7
1st Worker + 2nd Worker work in one hour = 1/3 + 1/7 = 10/21
Complete work is completed by them in 21/10 hours
2/7th of the work is completed in 2/7*21/10 = 3/5 hours
