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answer is 52?

9C1 + 8C2 + 6C2 = 52.
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Total People = 9
Required = 5

Ans = selection*arrangement ( arragement coz any player can be designated any position)

9C5*5!
9!/4!

In my opinion ans = 15120. Kindly validate
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jim441
Total People = 9
Required = 5

Ans = selection*arrangement ( arragement coz any player can be designated any position)

9C5*5!
9!/4!

In my opinion ans = 15120. Kindly validate

This approach counts as arrangements the two forwards and two guards switching "positions" within their roles as same.

Posted from my mobile device
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jim441
Total People = 9
Required = 5

Ans = selection*arrangement ( arragement coz any player can be designated any position)

9C5*5!
9!/4!

In my opinion ans = 15120. Kindly validate

This approach counts as arrangements the two forwards and two guards switching "positions" within their roles as same.

Posted from my mobile device

Oh yeah you are right,the correct answer would be:

9C5*5!/(2!*2!)
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MartyTargetTestPrep
You need to take into account that you don't have 9 people to choose from after you have chosen the forwards, and that you don't have 7 people to choose from after you have chosen the guards.

So, what you have is mostly correct, but you need to adjust it to take into account that you are working with fewer people in each step after the first. See what happens when you make that adjustment.

Got the answer to match!
(9!/2!7!)*(7!/2!5!)*(5!/4!)=3,780

You rock!!!
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MartyTargetTestPrep
You need to take into account that you don't have 9 people to choose from after you have chosen the forwards, and that you don't have 7 people to choose from after you have chosen the guards.

So, what you have is mostly correct, but you need to adjust it to take into account that you are working with fewer people in each step after the first. See what happens when you make that adjustment.

Got the answer to match!
(9!/2!7!)*(7!/2!5!)*(5!/4!)=3,780

You rock!!!
Well done!
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Easy one. 9c2x7c2x5c1 =3780. After selecting the forwards, you have to select from remaining and same way the next time.
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Hi KarishmaB in this we are getting the right ans by doing 9C2 * 7C2 * 5C1 = 3780 but don't we need to divide it by 2! as we do when:

distributing 4 people in groups of 2 each = 4C2/2!

to correct for the repeat groups here?
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Natansha
Hi KarishmaB in this we are getting the right ans by doing 9C2 * 7C2 * 5C1 = 3780 but don't we need to divide it by 2! as we do when:

distributing 4 people in groups of 2 each = 4C2/2!

to correct for the repeat groups here?
In that case, the groups are identical. They are not "named" so to say. So from A, B, C, D, when I select 2 people, I can do it by selecting A, B giving me 2 groups as A, B and C, D or I can select C, D giving me two groups are A, B and C, D. This is double counting and hence division by 2.

But here, we select 9C2 for Forward positions so we select A, B for Forwards and 7C2 for guards so C, D for guards.
If I select C, D for Forward and A,B for guards, these are different selections. Hence there is no double counting here. Hence no division by 2!
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