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28 Nov 2022, 02:30
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:42) correct
27%
(02:00)
wrong
based on 52
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The number of children in a certain family is a prime number less than 10. The number of boys in the family is greater than the number of girls, and the number of boys is a prime number. If at least 1 of the children in the family is a girl, which of the following could be the number of boys in the family?
I. 2
II. 3
III. 5
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
I. 2
II. 3
III. 5
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
28 Nov 2022, 02:42
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Boys = x
Girls = y
x + y = a prime number <10
Also mentioned that x > y
Mentioned that at least one of the children is a girl.
-> y >=1
Considering that y can at least be "1",
Going by the options(for number of boys)-
[remember, that x + y should be a prime number]
i. 2
2+1 =3 --> prime number <10. This is a considerable option.
ii. 3
3+1=4 --> Not a prime. Not a considerable option.
iii. 5
5+1 =6 --> Not a prime. Not a considerable option.
Thus, the answer is: A. I only
Bunuel, please let me know if this approach is right.
Girls = y
x + y = a prime number <10
Also mentioned that x > y
Mentioned that at least one of the children is a girl.
-> y >=1
Considering that y can at least be "1",
Going by the options(for number of boys)-
[remember, that x + y should be a prime number]
i. 2
2+1 =3 --> prime number <10. This is a considerable option.
ii. 3
3+1=4 --> Not a prime. Not a considerable option.
iii. 5
5+1 =6 --> Not a prime. Not a considerable option.
Thus, the answer is: A. I only
Bunuel, please let me know if this approach is right.
