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11 Feb 2023, 14:12
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
70% (02:00) correct
30%
(02:05)
wrong
based on 610
sessions
History
Date
Time
Result
Not Attempted Yet
In 2000, the number of people using the internet was 44 4/9% of the number in 2003. What was the percentage change in internet users from 2000 to 2003?
(A) 44 4/9%
(B) 55 5/9%
(C) 120%
(D) 125%
(E) 225%
(A) 44 4/9%
(B) 55 5/9%
(C) 120%
(D) 125%
(E) 225%
13 Feb 2023, 08:54
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Let the number of people using the internet in 2003 be 100. Therefore, the number of people using the internet in 2000 will be \(44 \frac{4}{9}%\) of 100 = 44.44
Percentage change in internet users from 2000 to 2003 = \(\frac{(No. of Users in 2003 - No. of Users in 2000)}{No. of Users in 2000} * 100\)
% change = \(\frac{100 - 44.44}{44.44} * 100\)
or, % change = \(\frac{55.56}{44.44} * 100\) = 125%
Therefore, option D is correct
Percentage change in internet users from 2000 to 2003 = \(\frac{(No. of Users in 2003 - No. of Users in 2000)}{No. of Users in 2000} * 100\)
% change = \(\frac{100 - 44.44}{44.44} * 100\)
or, % change = \(\frac{55.56}{44.44} * 100\) = 125%
Therefore, option D is correct
lavanya.18
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13 Sep 2024, 00:13
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Let the number of people using the internet in 2003 be x
then people using the internet in 2000 would be 4/9x.
2000 2003
4/9x x
4x 9x
x 9/4x
Therefore, 9/4x can also be written as x+ 5/4x
So, the change is 5/4
5/4*100= 125% change ie. our answer.
D is the answer!
then people using the internet in 2000 would be 4/9x.
2000 2003
4/9x x
4x 9x
x 9/4x
Therefore, 9/4x can also be written as x+ 5/4x
So, the change is 5/4
5/4*100= 125% change ie. our answer.
D is the answer!
