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Laila12618
In a startup there are 120 employees. The average age is 25. If the number of female increased by half of its previous number and the number of males becomes 3/4th of its previous number, the total number of staff remains unchanged. The new average age is 22 years. Also it was observed that the average age of males and females remained unchanged. Find the average age of males now.
A. 25
B. 31
C. 13
D. 15
E. 23
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Solution:

  • Let number of male and female employees be m and f respectively
  • So initially we had \(m+f=120.....(i)\)
  • After which we had \(\frac{3m}{4}+\frac{3f}{2}=120\) or \(m+2f=160.....(ii)\)
  • Solving equation i and ii we get \(f=40\) and \(m=80\)

  • Average age in first scenario = 25
  • We can write \(m*a_m+f*a_f=25\times 120\) where \(a_m\) and \(a_f\) are average ages of male and female respectively
    \(⇒80a_m+40a_f=3000\)
    \(⇒2a_m+a_f=75.....(iii)\)

  • Average age in first scenario = 21
  • We can write \(\frac{3m}{4}*a_m+\frac{3f}{2}*a_f=21\times 120\)
    \(⇒60a_m+60a_f=2640\)
    \(⇒a_m+a_f=44.....(iv)\)

  • Solving equations iii and iv together we get \(a_m=31\)


Hence the right answer is Option B
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Deconstructing the Question

There are 120 employees with initial average age 25, so total initial age sum is \(120\cdot 25=3000\).

Let initial males be M, initial females be F, with \(M+F=120\).
Females increase by half, so \(F'=\frac{3}{2}F\).
Males become three-fourths, so \(M'=\frac{3}{4}M\).
Total remains 120, so \(\frac{3}{2}F+\frac{3}{4}M=120\).

Let male average age be a and female average age be b. These averages stay unchanged.
New overall average is 22, so new total age sum is \(120\cdot 22=2640\).

Step-by-step

From \(M+F=120\), write \(M=120-F\) and substitute into \(\frac{3}{2}F+\frac{3}{4}M=120\):

\(\frac{3}{2}F+\frac{3}{4}(120-F)=120\)

\(\frac{3}{2}F+90-\frac{3}{4}F=120\)

\(\frac{3}{4}F=30\)

\(F=40\)

Then \(M=80\), so \(F'=\frac{3}{2}\cdot 40=60\) and \(M'=\frac{3}{4}\cdot 80=60\).

Use weighted averages with constant group means:

Initial: \(80a+40b=3000\)
New: \(60a+60b=2640\) so \(a+b=44\)

Divide the initial equation by 40: \(2a+b=75\)
Substitute \(b=44-a\):

\(2a+(44-a)=75\)

\(a=31\)

Answer: B
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