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If x = 80%, by what percent is x larger than x^2?

(A) 8%
(B) 16%
(C) 20%
(D) 25%
(E) 80%

x = 80% = 0.8
x^2 = 0.8 * 0.8 = 0.64

Percent by which x is larger than x^2:

(x - x^2)/x^2 * 100 =
= (0.8 - 0.64)/0.64 * 100 =
= 0.25 * 100 =
= 25%

Answer: D.


tamsinlct
Hi,

Can you help walk me through your choice of (i) and (ii) for old and new in percentage change formula?

If we were to put x = Old and x^2 = New, then we have the following:

= (x^2 - x)/x
= ((80/100)^2 - (80/100)) / (80/100)
= (80/100) - 1
= -20%

So x is 20% larger than x^2


However, if we were to put x^2= new, and x = old, then we have the following:

= (x - x^2)/ x^2
= ((80/100) - (80/100)^2) /(80/100)^2
= (20/100)*(100/80)
=1/4 = 25%

So x is 25% larger than x^2

Or am I missing something/making a mistake somewhere?



The general formula for calculating percent increase or decrease (percent change) is: \(\frac{\text{Difference in values}}{\text{Reference value}}*100\). The reference value is the value you are comparing to. This means the reference value always goes in the denominator of the formula.

(When we are talking about percentage change from old value to new value, it would be \(\frac{\text{New Value - Old Value }}{\text{Old Value}}*100\).­)

In this question, we are comparing to x^2 (If x = 80%, by what percent is x larger than x^2?), so the reference value is x^2, which means it must go in the denominator.

Hope it's clear.­
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80% = 4/5
squaring it will give 16/25 and to see by how much percent 4/5 is greater its simply

16/25*x = 4/5

x=5/4
Or it is greater by 25%
Bunuel
If x = 80%, by what percent is x larger than x^2?

(A) 8%
(B) 16%
(C) 20%
(D) 25%
(E) 80%
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