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If the curve represented by \(y = x^2 – 5x + t\) intersects with the x-axis at two points and one of the points is (–1, 0), what is the other point?
Since the point (-1,0) lies on the curve y = x^2 – 5x + t, so the point satisfies the equation. Substituting x = -1 and y = 0, we get
\(0 = (-1)^2 -5(-1) + t\)
or 0 = 1 + 5 + t
=> t = -6
So equation of the curve is \(y = x^2 – 5x - 6\)
Now to find the other point which lies on x axis, we know that the y coordinate is 0, so we need to find the x coordinate
\(0 = x^2 - 5x - 6 \)
On solving, we get (x+1)(x-6) = 0
so x = -1 or x = 6
we know that (-1,0) is one point so the other point is (6,0) i.e., D is the answer.
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