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Bunuel
What is the value of \(\sqrt{\frac{10}{3\sqrt{11} + 10} + 30\sqrt{11}}\)


A. \(\sqrt{11}\)

B. \(\sqrt{33}\)

C. 8

D. 10

E. \(30\sqrt{11}\)


I truly don't understand why anyone would do the "real" math on this question rather than ballparking. Just ballpark. The square root of 11 is somewhere between 3 and 4...closer to 3...let's just try 3.3 and see what happens.

\(\sqrt{\frac{10}{10 + 10} + 30*3.3}\)

\(\sqrt{0.5+100} = 10\)

(Ahhh, notice that the second term will be the driving influence and it's going to be right around 100...it'll definitely be bigger than 64, and it'll definitely be smaller than 10000...only one answer choice is anywhere close.)

Answer choice D.

There seems to be some sort of pride for most students about doing the "real" math. But there are no bonus points for doing that. Set aside your pride and your need to follow the rules what academic math teachers have taught you...and just get the right answer as quickly as possible without all the steps that give you opportunities to get confused or make a silly mistake.

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Bunuel
What is the value of \(\sqrt{\frac{10}{3\sqrt{11} + 10} + 30\sqrt{11}}\)


A. \(\sqrt{11}\)

B. \(\sqrt{33}\)

C. 8

D. 10

E. \(30\sqrt{11}\)




\(\sqrt{\frac{10}{3\sqrt{11} + 10} + 30\sqrt{11}}\)

Rationalise the denominator first of all.

\(\sqrt{\frac{10*(10 -3\sqrt{11}) }{(10+3\sqrt{11})*(10 -3\sqrt{11})} + 30\sqrt{11}}\)

\(\sqrt{\frac{100 -30\sqrt{11} }{10^2 - 3^2*11} + 30\sqrt{11}}\)

\(\sqrt{100 -30\sqrt{11} + 30\sqrt{11}}\)

\(\sqrt{100}\)

\(= 10\)

Answer (D)

Hello Karishma,

why do you change the order of "3root(11)+10" into "10+3root(11)" in the denominator when rationalizing?

Thank you in advance!

Best regards
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↧↧↧ Detailed Video Solution to the Problem Series ↧↧↧



\(\sqrt{\frac{10}{3\sqrt{11} + 10} + 30\sqrt{11}}\)

Lets solve the first part of the term inside the square root

\(\frac{10}{3\sqrt{11} + 10}\)

To solve this we will rationalize the denominator by multiplying the numerator and the denominator with the conjugate of the denominator

=> \(\frac{10}{3\sqrt{11} + 10}\) = \(\frac{10}{3\sqrt{11} + 10} * \frac{3\sqrt{11} - 10}{3\sqrt{11} - 10}\)

Now, in the denominator we have the terms in the form \((a + b ) * (a - b) = a^2 - b^2\)

=> \(\frac{10 * 3\sqrt{11} - 10 }{(3\sqrt{11})^2 - 10^2}\)
= \(\frac{30\sqrt{11} - 100 }{9 * 11 - 100}\)
= \(\frac{30\sqrt{11} - 100 }{-1}\)
= \(100 - 30\sqrt{11}\)

=> \(\sqrt{\frac{10}{3\sqrt{11} + 10} + 30\sqrt{11}}\) = \(\sqrt{100 - 30\sqrt{11} + 30\sqrt{11}}\)
= \(\sqrt{100}\) = 10

So, Answer will be D
Hope it helps!

Watch the following video to learn How to Rationalize Roots

­
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Beko
Hello Karishma,

why do you change the order of "3root(11)+10" into "10+3root(11)" in the denominator when rationalizing?

Thank you in advance!

Best regards
This was done because \(10^2\) is greater than \((3\sqrt{11})^2\) and we will get -1 in the denominator otherwise.
We can solve it without changing the order also and then multiply with -1 as i did in my solution above.
Hope it helps!
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