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Bunuel
A can build up a structure in 8 days and B can break it is 3 days. A worked for 4 days and then is joined by B for two days. For these two days A is building and B is breaking. In how many days after that will A alone build up the remaining part of the structure?

A. 12

B. 11

C. 9

D. 22/3

E. 7


[textarea]This is a PS Butler Question


Solution:

The amount built in the first 4 days is 1/8 x 4 = 1/2.

The amount breaking in the next two days is:

(1/3 - 1/8) x 2 = (8/24 - 3/24) x 2 = 5/24 x 2 = 10/24 = 5/12

Thus, the amount now built is:

1/2 - 5/12 = 6/12 - 5/12 = 1/12.

To build the remaining 11/12, it will the following number of days:

(11/12)/(1/8) = 88/12 = 22/3 days.

Answer: D
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A can build up a structure in 8 days and B can break it is 3 days. A worked for 4 days and then is joined by B for two days. For these two days A is building and B is breaking. In how many days after that will A alone build up the remaining part of the structure?
A works for 4 days and completes 1/2 work
in next 2 days A does 1/4 work and B breaks 2/3 work
After 6 days, in effect we have (1/2 + 1/4 - 2/3) = 1/12 work
So, A has to do the balance of 11/12 work and to complete that he needs 8*11/12 = 22/3 days

Answer D
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Let the work done be 1 unit. Work Done = Time Taken × Rate of Work.

A can build up a structure in 8 days and B can break it is 3 days.
A's rate of work = 1/ 8, B's rate of work= (-)1/3

Work done by A in 6 days (4 days alone and 2 days along with B) = 6 * (1/8) = 3 / 4
Work done by B in 2 days when he was with A = (-) 2* 1/3

Net work done in 6 days = 3/4 - 2/3 = 1/12
Pending work = 1 - 1/12 = 11 /12

Pending Work for A = Time Required × A's Rate of Work.
11/12 = Time required x 1/8
=> Time required = 11 * 8 /12 = 22 / 3
Answer D
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