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What is the units digit of \(17^{7}\)?

When we need to find units digit of any power then units digit is same as the units digit of the base raised to the exponent.

=> Units digit of \(17^{7}\) = Units digit of \(7^{7}\)

Now to find the unit's digit of \(7^{7}\), we need to find the pattern / cycle of unit's digit of power of 7 and then generalizing it.

Unit's digit of \(7^1\) = 7
Unit's digit of \(7^2\) = 9
Unit's digit of \(7^3\) = 3
Unit's digit of \(7^4\) = 1
Unit's digit of \(7^5\) = 7

So, unit's digit of power of 7 repeats after every \(4^{th}\) number.
=> We need to divided 7 by 4 and check what is the remainder
=> 7 divided by 4 gives 3 remainder

=> \(7^{7}\) will have the same unit's digit as \(7^3\)
=> Unit's digits of \(7^{7}\) = 3

So, Answer will be B
Hope it helps!

Link to Theory for Last Two digits of exponents here.

Link to Theory for Units' digit of exponents here.
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