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Bunuel
When the positive integers m and n are divided by the positive integer d, they yield remainders of 17 and 27, respectively. If m + n, when divided by d, results in a remainder of 7, what is the value of d?

A. 34
B. 37
C. 44
D. 47
E. 51

If a divisor is positive, then the remainder is ALWAYS less than the divisor.

So,

27 < d

To solve this problem, we can use the “remainders can be added” concept. According to this concept, the remainder of a sum of integers is ALWAYS equal to the remainder of the sum of the remainders.

17 + 27 = 44 = (d)(q) + 7, where q is an integer quotient.

(d)(q) = 44 – 7 = 37

We see that d is a factor of 37 such that d is greater than 27. Since 37 is a prime number, the only possible value of d is 37 itself.

Answer: B
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given
17 = d*x + 17
27 = d*x+27
let x be 0 so d can be any value>27
now 17+27 ; 44
44-7 ; 37
d has to be 37 and x is 0 sufficient with the condition of question...
option B

Bunuel
When the positive integers m and n are divided by the positive integer d, they yield remainders of 17 and 27, respectively. If m + n, when divided by d, results in a remainder of 7, what is the value of d?

A. 34
B. 37
C. 44
D. 47
E. 51
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