Events & Promotions
| Last visit was: 14 Sep 2026, 09:26 |
It is currently 14 Sep 2026, 09:26 |
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
15 Nov 2023, 02:30
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
57% (03:11) correct
43%
(03:27)
wrong
based on 117
sessions
History
Date
Time
Result
Not Attempted Yet
At the start of a certain week, a school library had 100 comic books, all of which were on the shelf on Monday morning. 25% of the comic books issued on Tuesday and 12.5% of the comic books issued on Wednesday were returned by Saturday morning. Books are issued only on Tuesdays and Wednesdays. Number of comic books issued on Wednesday were twice the number of comic books issued on Tuesday during that week. If there are at least 40 comic books in the library that Saturday morning, what could be the greatest number of books that could he issued during that week?
A) 24
B) 48
C) 72
D) 80
E) 90
A) 24
B) 48
C) 72
D) 80
E) 90
15 Nov 2023, 14:34
Kudos
Bookmarks
The answer is (C).
Books issued on Tuesday = x
Books issued on Wednesday = 2x
--> Total books issued = 3x
Books issued on Tuesday not returned = x * (75/100) = 3x/4
Books issued on Wednesday not returned = 2x * (87.5/100) = 7x/4
--> Books available on Saturday morning:
100 - (3x/4) - (7x/4) >= 40
60 >= (3x/4) + (7x/4)
10x/4 <= 60
x <= 24
(Total books issued) --> 3x <= 72
Books issued on Tuesday = x
Books issued on Wednesday = 2x
--> Total books issued = 3x
Books issued on Tuesday not returned = x * (75/100) = 3x/4
Books issued on Wednesday not returned = 2x * (87.5/100) = 7x/4
--> Books available on Saturday morning:
100 - (3x/4) - (7x/4) >= 40
60 >= (3x/4) + (7x/4)
10x/4 <= 60
x <= 24
(Total books issued) --> 3x <= 72
General Discussion
22 Jul 2025, 12:36
Kudos
Bookmarks
Let books issued on Tuesday = \(T\)
Let books issued on Wednesday = \(W\)
Let remaining books (books that were not issued on either Tuesday or Wednesday) = \(R\)
\(T+W+R=100\) and \(W=2T\)
\(3T+R=100\)
\(R=100-3T\)
\(25\)% of the comic books issued on Tuesday and \(12.5\)% of the comic books issued on Wednesday were returned by Saturday morning and there were ateast \(40\) books on Saturday morning (including the remaining books).
\(0.25T+0.125W+R >= 40\)
\(0.25T+0.25T+R >= 40\)
\(0.5T+100-3T >= 40\)
\(-2.5T >= -60\)
\(T <= 24\)
The maximum value of \(T\) is \(24\). So the max value of \(W\) is \(2T = 2*24 = 48\)
The greatest number of books that could be issued that week is \(24+48 = 72\)
Let books issued on Wednesday = \(W\)
Let remaining books (books that were not issued on either Tuesday or Wednesday) = \(R\)
\(T+W+R=100\) and \(W=2T\)
\(3T+R=100\)
\(R=100-3T\)
\(25\)% of the comic books issued on Tuesday and \(12.5\)% of the comic books issued on Wednesday were returned by Saturday morning and there were ateast \(40\) books on Saturday morning (including the remaining books).
\(0.25T+0.125W+R >= 40\)
\(0.25T+0.25T+R >= 40\)
\(0.5T+100-3T >= 40\)
\(-2.5T >= -60\)
\(T <= 24\)
The maximum value of \(T\) is \(24\). So the max value of \(W\) is \(2T = 2*24 = 48\)
The greatest number of books that could be issued that week is \(24+48 = 72\)
Moderator:
