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As stated:

P = 101Q1 +10

P = 11Q2 + 10

So,

101Q1 = 11Q2

Since 101 and 11 share no common factors, their least common multiple occurs when:

Q1 = 11 and Q2 = 101

Since Q1/11 = Q3 + r/11

11/11 = 1 + 0/11 so

r = 0

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given p=101q+10-------i
and p divided by 11 leaves reminder of 10 OR p-10 is divisible by 11-------ii
from i and ii
101q is divisible by 11 ,
since 101 is not divisible by 11
so its certain that q is divisible by 11 or the remainder is 0 when q is divided by 11.
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