If n is the remainder when 123,456,789 is divided by 4 and m is the re

Question

If n is the remainder when 123,456,789 is divided by 4 and m is the remainder when 987,654,321 is divided by 8, what is the sum of n and m?

A. 2
B. 3
C. 4
D. 5
E. 6

VibhuAnurag · Answer

The answer is A.

The last two digits of 123,456,789 are 89 --> 89/4 --> n = 1
The last three digits of 987,654,321 are 321 --> 321/8 --> m = 1

--> n + m = 2

uCS2020 · Answer

To solve this question,what you need know is

Last 2 digits of the number divided by 4 tells you if it is divisible by 4 (  and tells you the remainder )
Last 3 digits of the number tells you if it is divisible by 8(same as the highlighted words)

123,456,789/4 = 89/4 = remainder 1
987,654,321/8 = 321/8 = remainder 1
1+1=2

Answer = A

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BrushMyQuant · Answer

n is the remainder when 123,456,789 is divided by 4

Theory : Remainder of a number by 4 = Remainder of last two digits of the number by 4 
  
=> Remainder of  123,456,789  by 4 = Remainder of 89 by 4 = 1

m is the remainder when 987,654,321 is divided by 8

Theory : Remainder of a number by 8 = Remainder of last three digits of the number by 8

=> Remainder of  987,654,321  by 8 = Remainder of 321 by 8 = 1

What is the sum of n and m

m + n = 1 + 1 = 2

So,  Answer will be A 
Hope it helps!

Playlist on Solved Problems on Remainders  here

Watch the following video to MASTER Remainders

https://www.youtube.com/watch?v=P0S6j2uTaj4

If n is the remainder when 123,456,789 is divided by 4 and m is the re

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GMAT Problem Solving (PS) Questions

If n is the remainder when 123,456,789 is divided by 4 and m is the re

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