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If x is a positive integer, and \(m=3^{(x+1)}\), what is \(9^{2x}\) in terms of m?

\(m=3^{(x+1)} = 3^x*3\) which gives \(\frac{m}{3}= 3^x\) and
\(9^{2x} = 3^{4x} = 3^x * 3^x * 3^x * 3^x = \frac{m}{3} * \frac{m}{3} * \frac{m}{3} * \frac{m}{3} = \frac{m^4}{81}\)

(A) \(\frac{m^2}{9}\)

(B) \(\frac{m^2}{81}\)

(C) \(\frac{m^3}{9}\)

(D) \(\frac{m^4}{3}\)

(E) \(\frac{m^4}{81}\)

Answer E.
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As x is +ve integer, we can put x=1 and then solve. The answer comes E.

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Bunuel
If x is a positive integer, and \(m=3^{(x+1)}\), what is \(9^{2x}\) in terms of m?


(A) \(\frac{m^2}{9}\)

(B) \(\frac{m^2}{81}\)

(C) \(\frac{m^3}{9}\)

(D) \(\frac{m^4}{3}\)

(E) \(\frac{m^4}{81}\)



\(m=3^{(x+1)}=3*3^x\).

\(9^{2x}=3^{4x}=(3^x)^4\). From above \(3^x=\frac{m}{3}\). Therefore, \((3^x)^4=(\frac{m}{3})^4=\frac{m^4}{81}\).

Answer: E.
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