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N*15units
5 days working, N workers have done N*5 units of work, and the remaining work is
N*15-N*5 = N*10 units
(N+8)*16 units
N*10=(N+8)*6
4n=48
N=12

IMO-D

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N workers can finish a job in 15 days. After working 5 days, additional 8 workers joined them. Together, they finished remaining job in 6 days. What is the value of n?

A. 15
B. 18
C. 24
D. 12
E. 9

We know that it takes 15 days to complete the work. Now that 5 days work is done we now have \(\frac{1}{3}\) work done since \(\frac{5}{15}\) and left with \(1 - \frac{1}{3} = \frac{2}{3}\) work to be done by N + 8 workers in 6 days.
Now, the fraction of number of persons who worked initially(N) and numbers of persons who worked later(N+8) would be equal to the ratio of work left to be done and work done in 6 days(6 units). Here the assumption is that rate of work done by individual is same foe each worker.
Thus,
\(\frac{N}{N+8} = \frac{6}{10}\)
10N = 6N + 48
N = 12

Answer D.­
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