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10 Mar 2024, 21:42
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
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Question Stats:
79% (02:57) correct
21%
(02:50)
wrong
based on 87
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A man has 720 grams of silver, 800 grams of copper and 1.3 kg of Zinc. He melts each of these metals to make a 1.48 kg alloy where the ratio of silver, copper and Zinc is 12:10:15 respectively. Find the respective ratio of remaining quantities of pure silver, pure copper and pure zinc left with him after making the alloy.
(A) 12:20:35
(B) 30:12:35
(C) 25:12:35
(D) 40:12:35
(E) None of these
(A) 12:20:35
(B) 30:12:35
(C) 25:12:35
(D) 40:12:35
(E) None of these
10 Mar 2024, 22:49
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We have common multiple as x:
12x+10x+15x = 1480
x= 40
Silver used = 12x = 480
Copper used = 10x = 400
Zinc used = 15x = 600
Silver remaining = 720-480 = 240
Copper remaining = 800-400 = 400
Zinc remaining = 1300-600 = 700
Ratio of remaining qty = 240:400:700 = 12:20:35
12x+10x+15x = 1480
x= 40
Silver used = 12x = 480
Copper used = 10x = 400
Zinc used = 15x = 600
Silver remaining = 720-480 = 240
Copper remaining = 800-400 = 400
Zinc remaining = 1300-600 = 700
Ratio of remaining qty = 240:400:700 = 12:20:35
21 Aug 2025, 10:14
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