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gmatophobia
Quant Chat Moderator
Joined: 22 Dec 2016
Last visit: 09 Sep 2026
Posts: 3,174
Location: India
Concentration: Strategy, Leadership
Posts: 3,174
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:52) correct
25%
(02:09)
wrong
based on 83
sessions
History
Date
Time
Result
Not Attempted Yet
A rectangular array consists of 1105 cans with no can placed on top of another. If each row in the array consists of the same number of cans, which of the following could NOT be the number of rows in the array?
A. 5
B. 13
C. 17
D. 25
E. 85
_________________
A. 5
B. 13
C. 17
D. 25
E. 85
_________________
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Power of Tiny Gains
1.01^(365) = 37.78
0.99^(365) = 0.03
Power of Tiny Gains
1.01^(365) = 37.78
0.99^(365) = 0.03
gmatophobia
Quant Chat Moderator
Joined: 22 Dec 2016
Last visit: 09 Sep 2026
Posts: 3,174
Location: India
Concentration: Strategy, Leadership
Posts: 3,174
gmatophobia
The question aims to test the concept of divisibility
1105 = 5 * 221 = 8 * 17 * 13
As the number of cans in each row is the same, 1105 should be completely divisible by all except the correct option.
Answer Choice Elimination
A. 5 ⇒ \(\frac{1105}{5}\) = Integer. Hence we can eliminate A.
B. 13 ⇒ \(\frac{1105}{13}\) = Integer. Hence we can eliminate B.
C. 17 ⇒ \(\frac{1105}{17}\) = Integer. Hence we can eliminate C.
D. 25 ⇒ \(\frac{1105}{25} \neq\) Integer. Correct option.
E. 85 ⇒ \(\frac{1105}{85}\) = Integer. Hence we can eliminate E.
Option D
_________________
Want to discuss quant questions and strategies : Join the quant chat group today
Power of Tiny Gains
1.01^(365) = 37.78
0.99^(365) = 0.03
Power of Tiny Gains
1.01^(365) = 37.78
0.99^(365) = 0.03
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