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19 Apr 2024, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
67% (01:22) correct
33%
(01:24)
wrong
based on 131
sessions
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If x and y are positive integers, what percent of three more than y is twice the value of x?
A \(\frac{1}{200x(y + 3)}\)
B \(\frac{y + 3}{200x}\)
C \(\frac{100(y + 3)}{2x}\)
D \(\frac{200x}{y} + 3\)
E \(\frac{200x}{y + 3}\)
A \(\frac{1}{200x(y + 3)}\)
B \(\frac{y + 3}{200x}\)
C \(\frac{100(y + 3)}{2x}\)
D \(\frac{200x}{y} + 3\)
E \(\frac{200x}{y + 3}\)
19 Apr 2024, 05:43
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E should be the answer. .
The reqd percentage , say = p
p ( y+3) / 100 = 2*x
p = 200*x / y + 3
The reqd percentage , say = p
p ( y+3) / 100 = 2*x
p = 200*x / y + 3
19 Apr 2024, 21:29
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Let unknow percent be T%
T% * (3+y)=2x
T%=2x/(y+3)
T=2x*100/(3+y)
T=200x/(3+y)
Option E.
T% * (3+y)=2x
T%=2x/(y+3)
T=2x*100/(3+y)
T=200x/(3+y)
Option E.
