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| Last visit was: 24 Apr 2026, 21:22 |
It is currently 24 Apr 2026, 21:22 |
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76% (00:37) correct
24%
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| As we have |k| in the equation so we will have two cases | |
| -Case 1: k ≥ 0 => |k| = k => \(k*k = 4\) => \(k^2 = 4\) => k = -2 or k = 2 But condition was k ≥ 0 => k = 2 is a SOLUTION | -Case 2: k ≤ 0 => |k| = -k => \(k * -k = 4\) => \(-k^2 = 4\) => \(k^2 = -4\) But square of a number cannot be negative => NO SOLUTION |
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