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01 May 2024, 01:30
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
42% (01:08) correct
58%
(00:58)
wrong
based on 280
sessions
History
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Time
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Not Attempted Yet
If \(a\), \(b\), and \(c\) are positive constants, how many different numbers \(y\) are there such that \(a*y + b = c\)?
A. 0
B. 1
C. 2
D. Infinitely many
E. Cannot be determined from the given information
A. 0
B. 1
C. 2
D. Infinitely many
E. Cannot be determined from the given information
05 May 2024, 20:30
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Official Solution:
If \(a\), \(b\), and \(c\) are positive constants, how many different numbers \(y\) are there such that \(a*y + b = c\)?
A. 0
B. 1
C. 2
D. Infinitely many
E. Cannot be determined from the given information
Since \(a\) is nonzero, then \(y = \frac{c - b}{a} = \frac{c - b}{nonzero \ number}\).
As a result, regardless of the value of \(c - b\), the equation \(a*y = c - b\) will always have only one solution, given by: \(y =\frac{c - b}{nonzero \ number}\).
Answer: B
If \(a\), \(b\), and \(c\) are positive constants, how many different numbers \(y\) are there such that \(a*y + b = c\)?
A. 0
B. 1
C. 2
D. Infinitely many
E. Cannot be determined from the given information
Since \(a\) is nonzero, then \(y = \frac{c - b}{a} = \frac{c - b}{nonzero \ number}\).
As a result, regardless of the value of \(c - b\), the equation \(a*y = c - b\) will always have only one solution, given by: \(y =\frac{c - b}{nonzero \ number}\).
Answer: B
General Discussion
01 May 2024, 01:54
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Bunuel
For a given value of \(a, b, \)and \(c\) there will always be only one value of \(y\) for which the equation holds true.
For example:
Let's assume
- \(a = 2 \)
- \(b = 6 \)
- \(c = 12\)
\(2 * y + 6 = 12\)
\(y = 3\)
Now, for any other value of \(y\), the value of \(a, b,\) or \(c\) will change.
Option B
