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Difficulty:
45%
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Question Stats:
68% (02:24) correct
32%
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A man sells seven different sized balls. Each ball costs n dollar more than the next one below it in size , and the price of the biggest ball is $ 46. If the sum of the prices of the seven different balls is $ 196 , what is the value of n ?
A) 6
B) 7
C) 8
D) 9
E) None
A) 6
B) 7
C) 8
D) 9
E) None
01 May 2024, 08:37
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Form a equation.
Here I will start from smallest to largest ball
46-6n+46-5n+46-4n+46-3n+46-2n+46-n+46=196
322-21n = 196
n= 6
Posted from my mobile device
Here I will start from smallest to largest ball
46-6n+46-5n+46-4n+46-3n+46-2n+46-n+46=196
322-21n = 196
n= 6
Posted from my mobile device
01 May 2024, 20:06
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Let Ball prices from 1st ball to 7th ball are given as a+n, a+2n.....a+7n
7th ball price = a+7n= $46
Sum of all ball prices is = 7a+28n =$196
On solving these two equations, we get n =6 and a=4.
7th ball price = a+7n= $46
Sum of all ball prices is = 7a+28n =$196
On solving these two equations, we get n =6 and a=4.
