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29 May 2024, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:35) correct
20%
(01:47)
wrong
based on 130
sessions
History
Date
Time
Result
Not Attempted Yet
When \(3x^2 + nx + 5 = 0\) has only one solution, n=?
(A) \(\sqrt{48}\)
(B) \(\sqrt{80}\)
(C) \(10\)
(D) \(3\sqrt{2}\)
(E) \(\sqrt{60}\)
(A) \(\sqrt{48}\)
(B) \(\sqrt{80}\)
(C) \(10\)
(D) \(3\sqrt{2}\)
(E) \(\sqrt{60}\)
29 May 2024, 03:18
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Bunuel
for one solution B^2 - 4AC = 0, B^2 = 4AC
n^2 = 4 * 3 * 5
Therefore, n = \(\sqrt{60}\)
Hence E.
General Discussion
29 May 2024, 04:04
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Answer: E
Concept:
1) 2 distinct real roots when b^2 - 4*a*c > 0
2) Number of roots = 1 / identical roots when b^2 - 4*a*c = 0 [root is -b / 2a]
3) No real roots when b^2 - 4*a*c < 0
Question is asking about "2)" so using that we get n = root(60)
Concept:
1) 2 distinct real roots when b^2 - 4*a*c > 0
2) Number of roots = 1 / identical roots when b^2 - 4*a*c = 0 [root is -b / 2a]
3) No real roots when b^2 - 4*a*c < 0
Question is asking about "2)" so using that we get n = root(60)
