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howardsh
I got confused in this mock...and chose B. How do you know if we need to include 16 families who's got exactly 3 television sets? Especially when the question is saying "families surveyed that owned fewer than 3 television sets..."? Otherwise I would've gotten 51 instead of 35.
­Question clearly says " For the familes surveyed that owned fewer than \(3\) televison sets ". So why would you include familes that owned \(3\) televison sets.

\(20\) familes owned \(2\) televison sets and \(11 \) familes owned \(1\) televison set.

Hence total televison owned \(= 20*2 + 11*1 = 51\)

Hope it helped.­
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stne

howardsh
I got confused in this mock...and chose B. How do you know if we need to include 16 families who's got exactly 3 television sets? Especially when the question is saying "families surveyed that owned fewer than 3 television sets..."? Otherwise I would've gotten 51 instead of 35.
­Question clearly says " For the familes surveyed that owned fewer than \(3\) televison sets ". So why would you include familes that owned \(3\) televison sets.

\(20\) familes owned \(2\) televison sets and \(11 \) familes owned \(1\) televison set.

Hence total televison owned \(= 20*2 + 11*1 = 51\)

Hope it helped.­
­ahhh got it. thanks
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There is a significant trap here. 35 vs 51. I went in that trap.
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I fell into the 35 trap as well. Upon closer inspection, the question is asking us to find the total number of TVs owned among families that owned fewer than 3 TVs.

If it was asking to find the total number of families only that own fewer than 3 TVs, the answer would be 4+11+20=35.

But since its asking for the total number of TVs, we multiply the number of families with the number of TVs, hence:
(4x0) + (11x1) + (20x2) = 51.
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