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I felt a little confused by the statements, st1 8 to 5 while st2 and st3 have and. Was that intentional?
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I felt a little confused by the statements, st1 8 to 5 while st2 and st3 have and. Was that intentional?
­
That was a typo. Edited now.
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In this case you can form an equation and quickly test the options as well,

Given: m=4a, n=3a
Increased in the ratio of 1:1; let this increase be "k"
The new ratio is now 4a+k:3a+k

You can notice that this can be quickly solved for "a" if we equate the options and subtract two equations

1. 8 and 5

Solving for "a" will give us a = 3; m=12; n=9; k=-4 => not possible as ratio is increased by 1:1

2. 25 and 21

Solving for "a" will give us a = 4; m=16; n=12; k=9 => possible

3. 13 and 11

Solving for "a" will give us a = 2; m=8; n=6; k=5 => possible

Answer A
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­The ratio of two positive integers, \(m\) and \(n\), is 4 to 3. If the values of \(m\) and \(n\) are increased in a ratio of 1 to 1, which of the following cannot be the resulting integers?

The resulting integers are 4a + k and 3a + k.

So, we can solve this one quickly by noticing that the difference between the two resulting integers must be a.

So, to check each pair, plug in the difference between the two integers as a.

I. 8 and 5

a = 8 - 5 = 3

4 × 3 = 12

Since the first original integer cannot be 12, this pair cannot work.

II. 25 and 21

a = 25 - 21 = 4.

4 × 4 = 16

3 × 4 = 12

25 - 16 = 9

21 - 16 = 9

k = 9

This pair works.

III. 13 and 11

a = 13 - 11 = 2

4 × 2 = 8

3 × 2 = 6

13 - 8 = 5

11 - 6 = 5

k = 5

This pair works.

The question asks which cannot work.

A. I only
B. II only
C. III only
D. I and II only
E. I and III only­


Correct answer: A
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