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­Volume of first block: \(5 * 6 * 12 = 360 m^3\)
10 workers need 12h for \(360m^3\), that is their hourly rate is \(\frac{360m^3}{12h} = 30 m^3/h\)­
Work rate per worker therefor is :\( \frac{30}{10} m^3/h =3m^3/h\)

Volume of second block: \( (5 + 1) * (6 + 2) * (12 + 3) = 720 m^3\)
Given 12 workers with work rate as above, for \(720 m^3\) they need:\(\frac{ 720}{ (12*3)} = 20h\)

IMO: D­
­Hi i hade one question,

Why when calculating for second block, when calculating the work rate, you have you included 12*3? Where did this 3 come from?

Thanks
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Ratanp

felixf0800
­Volume of first block: \(5 * 6 * 12 = 360 m^3\)
10 workers need 12h for \(360m^3\), that is their hourly rate is \(\frac{360m^3}{12h} = 30 m^3/h\)­
Work rate per worker therefor is :\( \frac{30}{10} m^3/h =3m^3/h\)

Volume of second block: \( (5 + 1) * (6 + 2) * (12 + 3) = 720 m^3\)
Given 12 workers with work rate as above, for \(720 m^3\) they need:\(\frac{ 720}{ (12*3)} = 20h\)

IMO: D­
­Hi i hade one question,

Why when calculating for second block, when calculating the work rate, you have you included 12*3? Where did this 3 come from?

Thanks
­Work rate per worker is 3
Total work rate of 12 worker is = 12*3
To get time taken by 12 worker to complete the work total rate has to be considered.

Hope you get is now.
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