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(Sum of 9)/9 =1.1 * (Sum of 10)/10
(S9)/(S10) = 0.99

answer 99% E
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Bunuel
­In a particular course, Arif appeared in 10 quizzes. The average of his best 9 quizzes is 10% more than the average of all the quizzes he attended. The total marks obtained in best 9 quizzes is what % of the total marks obtained in 10 quizzes?

(A) 80%
(B) 88%
(C) 90%
(D) 95%
(E) 99%

­
­

Say average of 10 quizzes is 100. Sum of all 10 quizzes is 1000.
Then avg of 9 best quizzes is 10% more that so it is 110. Sum of best 9 quizzes is 990.

Percentage of marks obtained in best 9 quizzes is 990/1000 * 100 = 99%

Answer (E)
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