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A group of tourists needed to walk 45 miles. During the first day the group walked 19 miles. To complete the required distance during the second day, the group had to cover the distance which was approximately what percent greater than the distance walked during the first day?

The group walked during the first day = 19 miles
The group walked during the second day = 45-19= 26 miles
So, the group walked = 26-19=7 miles more in the second day
Which is 7/19*100= 7/20*100=35% approximately

Answer choice D is more closest to our approximation.

Answer: D.
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