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09 Oct 2024, 01:30
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Difficulty:
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85% (01:37) correct
15%
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If \(x ≠ 0\) or 1, then \(\frac{x^5-x^3}{x^3 -x^2} * \frac{x}{5}\) is equivalent to which of the following?
(A) \(\frac{x^2}{5}\)
(B) \(\frac{1}{x} + \frac{1}{x}\)
(C) \(\frac{x^2}{3}\)
(D) \(\frac{x^3+x^2}{5}\)
(E) \(x^3\)
(A) \(\frac{x^2}{5}\)
(B) \(\frac{1}{x} + \frac{1}{x}\)
(C) \(\frac{x^2}{3}\)
(D) \(\frac{x^3+x^2}{5}\)
(E) \(x^3\)
09 Oct 2024, 15:06
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\(\frac{x^5 - x^3 }{ x^3 - x^2} * \frac{x}{5}\)
\(\frac{x^3 (x^2 - 1) }{ x^2 (x - 1)} * \frac{x}{5}\)
\(x (x + 1) * \frac{x}{5}\)
\(\frac{x^3 + x^2 }{ 5}\)
Answer D.
\(\frac{x^3 (x^2 - 1) }{ x^2 (x - 1)} * \frac{x}{5}\)
\(x (x + 1) * \frac{x}{5}\)
\(\frac{x^3 + x^2 }{ 5}\)
Answer D.
