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24 Oct 2024, 01:30
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A
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The number of bananas harvested in 2000 was the integer x. In 2001, the number of bananas harvested grew by 150% from the year 2000. In 2002, the number of bananas harvested grew by 400% from the year 2000. What was the percentage growth in the number of bananas harvested from the year 2001 to the year 2002?
(A) 100%
(B) 167%
(C) 200%
(D) 250%
(E) 500%
(A) 100%
(B) 167%
(C) 200%
(D) 250%
(E) 500%
This is a PS Butler Question
Check the links to other Butler Projects:
Check the links to other Butler Projects:
- Data Sufficiency Butler
- Critical Reasoning Butler
- Reading Comprehension Butler
- Integrated Reasoning Butler
24 Oct 2024, 05:14
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\(\\
2000 - x\\
2001 - x*2.5\\
2002 - x*5\\
\)
Percentage growth from 2001 to 2002 will be:
\(\frac{5x - 2.5x}{2.5x} *100= 100%\)
Or, without calculation we notice, that a double growth from 2001 will give 2002's value. Double growth means a growth of 100%.
Hence, A
Hope it helps
2000 - x\\
2001 - x*2.5\\
2002 - x*5\\
\)
Percentage growth from 2001 to 2002 will be:
\(\frac{5x - 2.5x}{2.5x} *100= 100%\)
Or, without calculation we notice, that a double growth from 2001 will give 2002's value. Double growth means a growth of 100%.
Hence, A
Hope it helps
24 Oct 2024, 08:43
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Bananas harvested in 2000= x
In 2001= x(1+1.50)= 2.50*x
In 2002= x(1+4.00)= 5*x
Percentage growth in number of bananas from 2001 to 2002= [(5x-2.5x)/2.5x]*100 = 100%
Answer:A
In 2001= x(1+1.50)= 2.50*x
In 2002= x(1+4.00)= 5*x
Percentage growth in number of bananas from 2001 to 2002= [(5x-2.5x)/2.5x]*100 = 100%
Answer:A
