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P, Q and R are working on a project. Q alone would have been able to complete the project in two hours less than R would. If Q and R start working and Q leaves after three hours, then R would need one hour more to finish the work. If P and Q start working and P leaves after two hours, then Q would need one hour more to finish the work.

If all three of them together complete the work in less than 2 hours, then the ratio of the time taken by R alone to finish the work to that taken by P alone.

Let the time taken by P, Q & R working alone to complete the project be p, q & r hours respectively

Q alone would have been able to complete the project in two hours less than R would.
q = r - 2; r = q + 2

If Q and R start working and Q leaves after three hours, then R would need one hour more to finish the work.
3/q + 3/r + 1/r = 1
3/q + 4/(q+2) = 1
3(q+2) + 4q = q(q+2)
7q + 6 = q^2 + 2q
q^2 - 5q - 6 = 0
(q+1)(q-6) = 0
q = 6
r = q + 2 = 8

If P and Q start working and P leaves after two hours, then Q would need one hour more to finish the work.
2/p + 2/q + 1/q = 1
2/p + 3/6 = 1
2/p = 1/2
p = 4

If all three of them together complete the work in less than 2 hours, then the ratio of the time taken by R alone to finish the work to that taken by P alone.
1/p + 1/q + 1/r = 1/4 + 1/6 + 1/8 = (6+4+3)/24 = 13/24
Number of hours required = 24/13 < 2 hours

The ratio of the time taken by R alone to finish the work to that taken by P alone = r:p = 8:4 = 2:1

IMO D
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