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SkinBob
Can you please explain why there are 8 vacant spots when there are only 11 total terms and we have already placed the non-s letters?

Thank you!
Krunaal
Arranging Non-S letters first: 7!/4!2! = 105

_M_I_I_I_P_P_I_ => we have 8 vacant spaces for 4 S's

Selecting 4 from 8 vacant spaces: 8C4 = 70

Thus, no. of ways no 2 S letters are adjacent = 105*70 = 7350

Answer A.
After arranging 7 non-S letters, we can arrange the remaining S each anywhere in between of two already arranged letters, we take those as vacant spots, also the S can be a starting letter or the last letter hence that's a vacant spot too. We are selecting 4 vacant spots or places where to put each of our S, so the terms in total will always be 7+4 = 11, but 8 is the available "gaps" that we have for remaining 4 terms.
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