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Updated on: 15 Mar 2025, 06:55
Originally posted by mrfredrick on 13 Mar 2025, 00:25.
Last edited by mrfredrick on 15 Mar 2025, 06:55, edited 1 time in total.
Last edited by mrfredrick on 15 Mar 2025, 06:55, edited 1 time in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
97% (00:23) correct
3%
(01:38)
wrong
based on 75
sessions
History
Date
Time
Result
Not Attempted Yet
13 Mar 2025, 23:23
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This is a straightforward problem involving the difference of squares. formula:
\((a+b)(a-b) = a^2 - b^2\)
Here, \(a = 2\) and \(b = \sqrt{7}\). Applying the formula:
\((2 + \sqrt{7})(2 - \sqrt{7}) = 2^2 - (\sqrt{7})^2\)
Simplify:
\(2^2 = 4 \quad \text{and} \quad (\sqrt{7})^2 = 7\)
\(4 - 7 = -3\)
Final Answer:
The correct choice is B. -3.
\((a+b)(a-b) = a^2 - b^2\)
Here, \(a = 2\) and \(b = \sqrt{7}\). Applying the formula:
\((2 + \sqrt{7})(2 - \sqrt{7}) = 2^2 - (\sqrt{7})^2\)
Simplify:
\(2^2 = 4 \quad \text{and} \quad (\sqrt{7})^2 = 7\)
\(4 - 7 = -3\)
Final Answer:
The correct choice is B. -3.
14 Mar 2025, 02:46
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\((2+\sqrt{7})*(2-\sqrt{7})=2^2- \sqrt{7}^2=4-7=-3\)
Answer: B
Answer: B
