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HarshaBujji
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BhavikaA
got the right answer, unsure about approach.
You have 60 hours and 40 units of raw material
For type A you need 3 hours and 2 units of Raw mat.
So basically you can manufacture 20 type A widget

For type B you need 5 hours and 4 units :
So here will be able to manufacture at most 10 as 40 raw material/4 (req by Type B);
Since type A is max between A and B we choose 20 as the answer
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let be the no of type A and Type B is x and y resp.
so time rq. 3x+5y=60
material rq. 2x+4y=40
by solving these x+y=20, so the answer is 20
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In this question, the goal is maximize output.

This factory is capacity constrained with 60 hours of labor and 40 units of raw materials.

Note, the question does mention a minimum amount of A or B (be on the lookout for this).

Due to this, we can maximize output by only producing type A:

60 hours / 3 hours = 20 units
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