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ItIsOk
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You missed out the third possibility of
(x2−9x+19) be (-1) giving x=4,5 and at the same time (x2−17x+72) for (x=4,5 respectively to their corresponding values) be even thus adding 2 more solutions to the given problem making it total of 6 solutions altogether.

nirkr
My logic says this:
it's either x^0 or 1^x
considering x^0:
x^2-17x+172=0 --> (x-9)(x-8)=0 --> 2 solutions
considering 1^x:
x^2-9x+19=1 --> x^2-9x+18=0 --> (x-6)(x-3)=0 --> 2 solutions

IMO E. what am I missing?
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Here is a much better question with proper GMAT wording, testing the same concept, with good discussion and a detailed official solution:

https://gmatclub.com/forum/gmat-club-wo ... 95497.html
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