Bunuel
In 1991, a box seat at the theater cost $84.50 per ticket, and parking costs were $14.50 per vehicle. If, for the 1992 season, box ticket prices went up by 18 percent and parking costs went up by 10 percent, how much more did it cost one person with one vehicle to spend a night at the theater in 1992?
A. 17.50
B. 16.66
C. 16.50
D. 16.25
E. 14.50
In 1991,
Theatre box ticket cost = $84.50 per ticket.
Parking ticket cost = $14.50 per vehicle.
In 1992, the price has shown an increase of 18% in theatre box ticket cost, and 10% increase in vehicle parking cost.
We need to find the amount of increase from 1991 to 1992.
New price box ticket = 84.50 * (1+18%) = 84.50 * (118/100) = 99.71
New price Parking ticket = 14.50 * (1+10%) = 14.50 * (110/100) = 15.95
99.71 - 84.50 = $ 15.21 increase in box ticket price.
15.95 - 14.50 = $ 1.45 increase per parking ticket.
Total increase = $15.21 + $1.45 =
$16.66 Option B Alternate solution: Since, We need to find the amount increase. Let’s do it this way.
Box ticket price is $ 84.50
1% = 0.845
10% = 8.45
5% = half of 10% = 4.225
3% = 3*1% = 3 * 0.845 = 2.535
So, 18% = 10% + 5% + 3%
= 8.45 + 4.225 + 2.535
=
$ 15.21 Parking ticket price is $ 14.50
1% = 0.145
10% = 1.45
We need 10% only =
$ 1.45 Total increase = $15.21 + $1.45
=
$ 16.66 Option B